Optimal. Leaf size=81 \[ -\frac{1194}{125 \sqrt{2 x+3}}-\frac{66}{25 (2 x+3)^{3/2}}-\frac{26}{25 (2 x+3)^{5/2}}+12 \tanh ^{-1}\left (\sqrt{2 x+3}\right )-\frac{306}{125} \sqrt{\frac{3}{5}} \tanh ^{-1}\left (\sqrt{\frac{3}{5}} \sqrt{2 x+3}\right ) \]
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Rubi [A] time = 0.0784931, antiderivative size = 81, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.148, Rules used = {828, 826, 1166, 207} \[ -\frac{1194}{125 \sqrt{2 x+3}}-\frac{66}{25 (2 x+3)^{3/2}}-\frac{26}{25 (2 x+3)^{5/2}}+12 \tanh ^{-1}\left (\sqrt{2 x+3}\right )-\frac{306}{125} \sqrt{\frac{3}{5}} \tanh ^{-1}\left (\sqrt{\frac{3}{5}} \sqrt{2 x+3}\right ) \]
Antiderivative was successfully verified.
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Rule 828
Rule 826
Rule 1166
Rule 207
Rubi steps
\begin{align*} \int \frac{5-x}{(3+2 x)^{7/2} \left (2+5 x+3 x^2\right )} \, dx &=-\frac{26}{25 (3+2 x)^{5/2}}+\frac{1}{5} \int \frac{-9-39 x}{(3+2 x)^{5/2} \left (2+5 x+3 x^2\right )} \, dx\\ &=-\frac{26}{25 (3+2 x)^{5/2}}-\frac{66}{25 (3+2 x)^{3/2}}+\frac{1}{25} \int \frac{-147-297 x}{(3+2 x)^{3/2} \left (2+5 x+3 x^2\right )} \, dx\\ &=-\frac{26}{25 (3+2 x)^{5/2}}-\frac{66}{25 (3+2 x)^{3/2}}-\frac{1194}{125 \sqrt{3+2 x}}+\frac{1}{125} \int \frac{-1041-1791 x}{\sqrt{3+2 x} \left (2+5 x+3 x^2\right )} \, dx\\ &=-\frac{26}{25 (3+2 x)^{5/2}}-\frac{66}{25 (3+2 x)^{3/2}}-\frac{1194}{125 \sqrt{3+2 x}}+\frac{2}{125} \operatorname{Subst}\left (\int \frac{3291-1791 x^2}{5-8 x^2+3 x^4} \, dx,x,\sqrt{3+2 x}\right )\\ &=-\frac{26}{25 (3+2 x)^{5/2}}-\frac{66}{25 (3+2 x)^{3/2}}-\frac{1194}{125 \sqrt{3+2 x}}+\frac{918}{125} \operatorname{Subst}\left (\int \frac{1}{-5+3 x^2} \, dx,x,\sqrt{3+2 x}\right )-36 \operatorname{Subst}\left (\int \frac{1}{-3+3 x^2} \, dx,x,\sqrt{3+2 x}\right )\\ &=-\frac{26}{25 (3+2 x)^{5/2}}-\frac{66}{25 (3+2 x)^{3/2}}-\frac{1194}{125 \sqrt{3+2 x}}+12 \tanh ^{-1}\left (\sqrt{3+2 x}\right )-\frac{306}{125} \sqrt{\frac{3}{5}} \tanh ^{-1}\left (\sqrt{\frac{3}{5}} \sqrt{3+2 x}\right )\\ \end{align*}
Mathematica [A] time = 0.0997902, size = 63, normalized size = 0.78 \[ \frac{2}{625} \left (-\frac{5 \left (2388 x^2+7494 x+5933\right )}{(2 x+3)^{5/2}}+3750 \tanh ^{-1}\left (\sqrt{2 x+3}\right )-153 \sqrt{15} \tanh ^{-1}\left (\sqrt{\frac{3}{5}} \sqrt{2 x+3}\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.01, size = 71, normalized size = 0.9 \begin{align*} -{\frac{26}{25} \left ( 3+2\,x \right ) ^{-{\frac{5}{2}}}}-{\frac{66}{25} \left ( 3+2\,x \right ) ^{-{\frac{3}{2}}}}-{\frac{1194}{125}{\frac{1}{\sqrt{3+2\,x}}}}-{\frac{306\,\sqrt{15}}{625}{\it Artanh} \left ({\frac{\sqrt{15}}{5}\sqrt{3+2\,x}} \right ) }+6\,\ln \left ( 1+\sqrt{3+2\,x} \right ) -6\,\ln \left ( -1+\sqrt{3+2\,x} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.42293, size = 113, normalized size = 1.4 \begin{align*} \frac{153}{625} \, \sqrt{15} \log \left (-\frac{\sqrt{15} - 3 \, \sqrt{2 \, x + 3}}{\sqrt{15} + 3 \, \sqrt{2 \, x + 3}}\right ) - \frac{2 \,{\left (597 \,{\left (2 \, x + 3\right )}^{2} + 330 \, x + 560\right )}}{125 \,{\left (2 \, x + 3\right )}^{\frac{5}{2}}} + 6 \, \log \left (\sqrt{2 \, x + 3} + 1\right ) - 6 \, \log \left (\sqrt{2 \, x + 3} - 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.54128, size = 417, normalized size = 5.15 \begin{align*} \frac{153 \, \sqrt{5} \sqrt{3}{\left (8 \, x^{3} + 36 \, x^{2} + 54 \, x + 27\right )} \log \left (-\frac{\sqrt{5} \sqrt{3} \sqrt{2 \, x + 3} - 3 \, x - 7}{3 \, x + 2}\right ) + 3750 \,{\left (8 \, x^{3} + 36 \, x^{2} + 54 \, x + 27\right )} \log \left (\sqrt{2 \, x + 3} + 1\right ) - 3750 \,{\left (8 \, x^{3} + 36 \, x^{2} + 54 \, x + 27\right )} \log \left (\sqrt{2 \, x + 3} - 1\right ) - 10 \,{\left (2388 \, x^{2} + 7494 \, x + 5933\right )} \sqrt{2 \, x + 3}}{625 \,{\left (8 \, x^{3} + 36 \, x^{2} + 54 \, x + 27\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 49.5405, size = 126, normalized size = 1.56 \begin{align*} \frac{918 \left (\begin{cases} - \frac{\sqrt{15} \operatorname{acoth}{\left (\frac{\sqrt{15} \sqrt{2 x + 3}}{5} \right )}}{15} & \text{for}\: 2 x + 3 > \frac{5}{3} \\- \frac{\sqrt{15} \operatorname{atanh}{\left (\frac{\sqrt{15} \sqrt{2 x + 3}}{5} \right )}}{15} & \text{for}\: 2 x + 3 < \frac{5}{3} \end{cases}\right )}{125} - 6 \log{\left (\sqrt{2 x + 3} - 1 \right )} + 6 \log{\left (\sqrt{2 x + 3} + 1 \right )} - \frac{1194}{125 \sqrt{2 x + 3}} - \frac{66}{25 \left (2 x + 3\right )^{\frac{3}{2}}} - \frac{26}{25 \left (2 x + 3\right )^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.0917, size = 119, normalized size = 1.47 \begin{align*} \frac{153}{625} \, \sqrt{15} \log \left (\frac{{\left | -2 \, \sqrt{15} + 6 \, \sqrt{2 \, x + 3} \right |}}{2 \,{\left (\sqrt{15} + 3 \, \sqrt{2 \, x + 3}\right )}}\right ) - \frac{2 \,{\left (597 \,{\left (2 \, x + 3\right )}^{2} + 330 \, x + 560\right )}}{125 \,{\left (2 \, x + 3\right )}^{\frac{5}{2}}} + 6 \, \log \left (\sqrt{2 \, x + 3} + 1\right ) - 6 \, \log \left ({\left | \sqrt{2 \, x + 3} - 1 \right |}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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